ExtJS 3.x解决方案

尝试这样：

  cloneStore：function（originStore，newStore）{

 if（！newStore）{
 newStore = Ext.create（'Ext.data.Store'，{
 model：originStore模型
}）; 
} else {
 newStore.removeAll（true）; 
} 

 var records = []，originRecords = originStore.getRange（），i，newRecordData; 
 for（i = 0; i< originRecords.length; i ++）{
 newRecordData = Ext.ux.clone（originRecords [i] .copy（）。 
 newStore.add（new newStore.model（newRecordData，newRecordData.id））; 
} 

 newStore.fireEvent（'load'，newStore）; 

 return newStore; 
} 
 

注意： Ext.ux.clone 是一个分离的插件（你会发现它）使得一个对象的深层克隆。也许，Ext JS 4提供了一个熟悉的东西，我不知道..我使用这个特殊的克隆，因为Ext JS 3.x

有可能它需要在创建新商店时指定代理内存（现在我不确定，因为我始终使用提供的方式。

ExtJS 4.x解决方案

  function deepCloneStore ）{
 var target = Ext.create（'Ext.data.Store'，{
 model：source.model 
}）; 

 Ext.each source.getRange（），function（record）{
 var newRecordData = Ext.clone（record.copy（）。data）; 
 var model = new source.model（newRecordData，newRecordData.id）; 

 target.add（model）; 
}）; 

 return target; 
} 
 / pre> 
I'm trying to figure out how to clone an Ext.data.Store without keeping the old reference.

Let me explain better with some code. Here's the source store:
var source = Ext.create ('Ext.data.Store', {
    fields: ['name', 'age'] ,
    data: [
        {name: 'foo', age: 20} ,
        {name: 'boo', age: 30} ,
        {name: 'too', age: 10} ,
        {name: 'yoo', age: 80} ,
        {name: 'zoo', age: 30}
    ]
});
Follows an example of what I want to do:
var target = source;
target.removeAll ();
// Here I need to have target empty and source unchanged
// But in this case, source is empty as well
Now, in the above example the copy is done by reference while I need to do it by value.
So I found Ext.clone () in the docs but it seems it doesn't work for complex object, like Ext.data.Store:
var target = Ext.clone (source);
target.removeAll ();
// source is still empty
Then I tried with Ext.data.Model.copy () but the only way to do it work is this:
var target = Ext.create ('Ext.data.Store', {
    fields: ['name', 'age']
});

source.each (function (model) {
    target.add (model.copy ());
});
Now, for my reasons, I don't want to instantiate another Ext.data.Store, so I want to avoid this:
var target = Ext.create ('Ext.data.Store', {
    fields: ['name', 'age']
});
I'd like to have something like this:
var target;

source.each (function (model) {
    target.add (model.copy ());
});
But, obviously, it doesn't work.

So, how can I clone the source store?
ExtJS 3.x solution

Try this: 
cloneStore : function(originStore, newStore) {

    if (!newStore) {
        newStore = Ext.create('Ext.data.Store', {
            model : originStore.model
        });
    } else {
        newStore.removeAll(true);
    }

    var records = [], originRecords = originStore.getRange(), i, newRecordData;
    for (i = 0; i < originRecords.length; i++) {
        newRecordData = Ext.ux.clone(originRecords[i].copy().data);
        newStore.add(new newStore.model(newRecordData, newRecordData.id));
    }

    newStore.fireEvent('load', newStore);

    return newStore;
}
Note: Ext.ux.clone is a separated plugin (you will find it) which makes a deep clone of an object. Maybe, Ext JS 4 provides a familiar thing, I don't know.. I'm using this special clone since Ext JS 3.x

It is possible that it is required to specify the proxy memorywhen creating a new store (I'm not sure right now because I'm using always the "provided" way.

ExtJS 4.x solution
function deepCloneStore (source) {
    var target = Ext.create ('Ext.data.Store', {
        model: source.model
    });

    Ext.each (source.getRange (), function (record) {
        var newRecordData = Ext.clone (record.copy().data);
        var model = new source.model (newRecordData, newRecordData.id);

        target.add (model);
    });

    return target;
}