如果您的欧拉角表示绝对旋转，则可以计算旋转矩阵R.如何执行此操作取决于Euler角的定义，应在文档中进行描述.可能是:

If your Euler angles represent an absolute rotation, you can calculate a rotation matrix R. How you do this depends on the definition of the Euler angles, which should be described in the documentation. It might be:

R = rotateY(yaw) * rotateX(pitch) * rotateZ(roll)

同样，这只是一个例子.正确的公式取决于欧拉角的顺序及其解释.

Again, this is just an example. The correct formula depends on the order of Euler angles and their interpretation.

然后可以将相机的模型矩阵计算为:

The camera's model matrix can then be calculated as:

cam = translation(target) * R * translation(0, 0, radius)

(或对于左手坐标系为-radius). translation()计算转换矩阵.

(or -radius for left-handed coordinate systems). translation() calculates a translation matrix.

这背后的直觉是，将摄像机移至目标，然后根据R旋转它，然后再将其移回radius.

The intuition behind this is that you move your camera to the target, then rotate it according to R, and then move it back by radius.

如果具有此矩阵，则相机的向上矢量将是其第二列，眼睛矢量将是其第四列.如果只需要视图矩阵，请使用cam的逆矩阵.

If you have this matrix, the camera's up-vector will be its second column, the eye-vector will be its fourth column. If you just need a view-matrix, use cam's inverse.

注:上面的解释假定将向量视为列向量.如果将它们视为行向量(例如DirectX中的通用)，则必须对计算进行相应的调整.

Note: The explanations above assume that vectors are treated as column vectors. If they are treated as row vectors (e.g. common in DirectX), the calculations have to be adapted accordingly.