这取决于被调用来执行命令的 shell，但通常大多数 shell 使用 ; 来分隔命令，所以像这样应该工作:

That depends on the shell being invoked to execute the commands, but in general most shells use ; to separate commands so something like this should work:

command1; command2; command3

正如@dicroce 提到的，您可以使用 && 而不是 ; 这将在返回非零值的第一个命令处停止执行.这可能需要也可能不需要(并且某些命令可能会在成功时返回非零值)但是如果您尝试处理可能失败的命令，您可能不应该在 system() 调用中将多个命令串在一起，因为您没有任何确定故障发生位置的方法.在这种情况下，您***的选择是一次执行一个命令，或者创建一个 shell 脚本来执行适当的错误处理并调用它.

As @dicroce mentioned, you can use && instead of ; which will stop execution at the first command that returns a non-zero value. This may or may not be desired (and some commands may return non-zero on success) but if you are trying to handle commands that can fail you should probably not string multiple commands together in a system() call as you don't have any way of determining where the failure occured. In this case your best bet would either be to execute one command at a time or create a shell script that performs the appropriate error handling and call that instead.