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C ++指针数组初始化帮助

更新时间:2023-11-24 09:31:22

这个值初始化是标准C ++。



相关的标准是C ++ 98和C ++ 03§5.3.4/ 15。在C ++ 98它是默认初始化,在C + + 03和以后它的值初始化。对你的指针,他们都减少到零初始化。



C ++ 03§5.3.4/ 15:





–如果 new-initializer ()形式,则该项目是值初始化的(8.5);



在C ++ 0x中,该段落改为引用初始化规则8.5用于直接初始化,其中N3290 FDIS),你发现在§8.5/ 16中有相同的措辞。



hth。,


I had trouble with initializing arrays of pointers. What I found out compiling with gcc c++ (4.6.0) is:

MyClass** a = new MyClass*[100];

Does not always initalize the array of pointers. (most of the time it did give me an array of null pointers which confused me)

MyClass** a = new MyClass*[100]();

DOES initialize all the pointers in the array to 0 (null pointer).

The code I'm writing is meant to be be portable across Windows/Linux/Mac/BSD platforms. Is this a special feature of the gcc c++ compiler? or is it standard C++? Where in the standard does it says so?

This value-initialization is standard C++.

The relevant standardeese is in C++98 and C++03 §5.3.4/15. In C++98 it was default-initialization, in C++03 and later it's value initialization. For your pointers they both reduce to zero-initialization.

C++03 §5.3.4/15:

– If the new-initializer is of the form (), the item is value-initialized (8.5);

In C++0x that paragraph instead refers to “the initialization rules of 8.5 for direct-initialization”, where in N3290 (the FDIS) you find about the same wording in §8.5/16.

Cheers & hth.,