可以使用变量，使用一个字符串，期望编译器将其分裂。

You can use a variable, but you can't use a string and expect the compiler to magically split it up.

const char* ip = initializer.c_str();
const char* foo = new char[4]{ip[0], ip[1], ip[2], ip[3]};

一旦你有一个可变长度，但是，这根本不工作。你只需要分配，然后使用 string :: copy 在单独的步骤中填充数组。

Once you have a variable length, though, this doesn't work at all. You just have to allocate and then use string::copy to fill the array in a separate step.