最后找到一个解决方案

这是我如何做到的。而不是保存文件，我读取文件的内容，让xlrd读取它。

  def read_rows（inputfile）：$ b （$）$ b $ = 

 $ 
 rows.append（sh.row_values（rownum））
 return rows 
 

很好地工作，并将Excel文件转换成JSON格式。如果您想输出json，只需使用json.dumps（）。

完整的代码示例可以在 https://github.com/cjhendrix/HXLator/blob/master/gae/main.py ，它具有完整的实现的xlrd和如何处理数据。

Thx为指针

I am using xlrd in appengine. I use flask

I cant read the input file and it keeps on showing the same error message

the code is

def read_rows(inputfile):
    rows = []
    wb = xlrd.open_workbook(inputfile)
    sh = wb.sheet_by_index(0)
    for rownum in range(sh.nrows):
        rows.append(sh.row_values(rownum))
    return rows

@app.route('/process_input/',methods=['POST','GET'])
def process_input():
  inputfile = request.files['file']
  rows=read_rows(request.files['file'])
  payload = json.dumps(dict(rows=rows))
  return payload

I realize that this might be caused by not uploading and saving it as a file. Any workaround on this? This would help many others as well. Any help is appreciated, thx

Update: Found a solution that I posted below. For those confused with using xlrd can refer to the open source project repo I posted. The key is passing the content of the file instead of the filename

Find a solution finally

here's how I do it. Instead of saving the file, I read the content of the file and let xlrd reads it

def read_rows(inputfile):
  rows = []
  wb = xlrd.open_workbook(file_contents=inputfile.read())
  sh = wb.sheet_by_index(0)
  for rownum in range(sh.nrows):
    rows.append(sh.row_values(rownum))
  return rows

worked nicely and turned the excel files into JSON-able formats. If you want to output the json simply use json.dumps().

full code example can be found at https://github.com/cjhendrix/HXLator/blob/master/gae/main.py and it features full implementation of the xlrd and how to work with the data.

Thx for the pointers