您正在使用不包含/g(全局修饰符)的正则表达式运行循环.这意味着，每次您的正则表达式找到匹配项时，lastIndex属性都不会更改，并且在下一次迭代期间，将找到相同的匹配项，依此类推，以此类推，从而导致无限循环.

You are running a loop with a regex that does not contain a /g (global modifier). That means, that each time your regex finds a match, the lastIndex property will not change, and during the next iteration, the same match will be found, and so on and so forth, causing an infinite loop.

请参阅MDN上的 String#exec文档:

See String#exec documentation at MDN:

lastIndex   下一场比赛开始的索引.如果不存在"g"，则该值将保持为0.

lastIndex     The index at which to start the next match. When "g" is absent, this will remain as 0.

使用

let reg = /\([^)]+\)/g;

它将匹配所有 个出现的(，然后匹配除)之外的1个以上字符，然后匹配一个).

It will match all occurrences of (, then 1+ chars other than ) and then a ).