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分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

验证日期的EditText框

更新时间:2023-11-26 21:09:34

Java将处理\在字符串中作为起始的转义序列。请确保您使用\,而不是(这样你得到的字符串中的实际字符\),你应该没问题。

Java will treat \ inside a string as starting an escape sequence. Make sure you use \ instead (so that you get an actual \ character in the string) and you should be ok.

快速更新:作为艾蒂安指出,如果你真的想在正则表达式本身就是一个\,你需要使用\\,因为这将产生\在字符串,这将产生\在正则表达式。

Quick Update: As Etienne points out, if you actually want a \ in the RegEx itself, you'll need to use \\, since that will produce \ in the string, which will produce \ in the RegEx.

修正后您的正则表达式:

Your regex after correction:

String regEx ="^(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\\d{2}$";