您需要将 id 传递给您的 PHP 代码才能显示我认为的内容.例如，查看此问题的堆栈溢出 URL:http://***.com/questions/6520671/htaccess-rewrite-friendly-urls，它同时传递 id 和 slug.所以你可以有友好的 URL，比如:

You'll need to pass the id to your PHP code in order to display content I believe. For example, look at the Stack Overflow URL for this question: http://***.com/questions/6520671/htaccess-rewrite-friendly-urls where it is passing both id and slug. So you can have friendly URLs like:

http://www.myurl.com/13089093057550/this-is-a-nice-url

如果您决定采纳我的建议，那么这里是您在 .htaccess 中需要的代码:

If you decide to go by my suggestion then here is the code you will need in .htaccess:

Options +FollowSymlinks -MultiViews
RewriteEngine On

RewriteRule ^([0-9]*)/(.*)/?$ /content.php?id=$1&slug=$2 [L,QSA]