我猜使用 dynamic_cast 进行其他操作的真正简便方法是使用 std :: vector 而不是原始指针。

I guess the real easier way to do that other using dynamic_cast is using std::vector instead of a raw pointer.

示例代码

#include <string>
#include <iostream>
#include <vector>

struct Cat{
    virtual ~Cat() = default;
    virtual void meow() const = 0;
};

struct Meow : Cat{
    void meow() const override{ std::cout << "meow" << std::endl; }
};

int main()
{
    std::vector<Cat*> vec{100};
    vec[1] = new Meow();

    for(auto c : vec){
        if(auto m = dynamic_cast<Meow*>(c)){
            m->meow();
        }
    }

    // don't forget to release memory
    for(auto c : vec){
        delete c;
    }
}

实时示例

Live Example

现代版本，使用智能

#include <string>
#include <iostream>
#include <vector>
#include <memory>

struct Cat{
    virtual ~Cat() = default;
    virtual void meow() const = 0;
};
struct Meow : Cat{
    void meow() const override{ std::cout << "meow" << std::endl; }
};

int main()
{
    std::vector<std::unique_ptr<Cat>> vec{100};
    vec[1] = std::make_unique<Meow>();

    for(auto&& c : vec){
        if(auto m = dynamic_cast<Meow*>(c.get())){
            m->meow();
        }
    }

    // you don't need to manually clear the memory.
}

在线示例

Live Example