更新时间:2023-11-28 19:21:40
这个怎么样?
library(dplyr)
df1 %>%
mutate(first_name_1st2char = substr(first_name, 1, 2)) %>%
left_join(df2 %>% mutate(first_name_1st2char = substr(first_name, 1, 2)),
by = c("first_name_1st2char", "last_name", "year")) %>%
select(-first_name_1st2char)
输出为:
first_name.x last_name year first_name.y age
1 john asdf 2018 joe 12
2 jack qwerty 2017 jake 34
样本数据:
df1 <- structure(list(first_name = structure(c(2L, 1L), .Label = c("jack",
"john"), class = "factor"), last_name = structure(1:2, .Label = c("asdf",
"qwerty"), class = "factor"), year = c(2018, 2017)), .Names = c("first_name",
"last_name", "year"), row.names = c(NA, -2L), class = "data.frame")
df2 <- structure(list(first_name = structure(c(3L, 2L, 1L), .Label = c("donald",
"jake", "joe"), class = "factor"), last_name = structure(c(1L,
3L, 2L), .Label = c("asdf", "jong", "qwerty"), class = "factor"),
year = c(2018, 2017, 2018), age = c(12, 34, 5)), .Names = c("first_name",
"last_name", "year", "age"), row.names = c(NA, -3L), class = "data.frame")