更新时间:2023-11-28 23:21:10
不是很干净,但你可以尝试这样的东西(假设相同的数据生成过程)。
Not very clean but you can try something like this (assuming the same data generation process).
list.aID <- lapply(1:4, function(x) {
cbind(list[[(2*x) - 1]], list[[2*x]][1, 1, drop = FALSE])
})
all.aID <- rbind.fill(list.aID)
all.aID
all.aID
d1 d2 id1
1 0.68103 -0.74023 1
2 -0.50684 1.23713 2
3 0.33795 -0.37277 3
4 0.37827 0.56892 4