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分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

对“深度相等"进行功能检查.嵌套对象

更新时间:2023-11-29 12:02:10

一个简单的解决方案是对对象进行JSON字符串化并比较它们的字符串表示形式.正如@Jan所说的...

A simple solution would be to JSON stringify the objects and compare their string representations. As @Jan mentions ...

这仅在对象以完全相同的方式初始化时才有效 道路.如果属性相同但顺序不同,它将 失败

this will only work if the objects are initialized in the exact same way. If the properties are the same but in a different order, it will fail

...这有点脆弱,但可能适合您的目的.

...this is a bit brittle but may suit your purposes.