更新时间:2023-11-29 12:46:22
使用strtotime()
将包含日期的字符串转换为 Unix 时间戳:
<?php
// both lines output 813470400
echo strtotime("19951012"), "
",
strtotime("12 October 1995");
?>
您可以将结果作为第二个参数传递给 date()
自己重新格式化日期:
You can pass the result as the second parameter to date()
to reformat the date yourself:
<?php
// prints 1995 Oct 12
echo date("Y M d", strtotime("19951012"));
?>
strtotime()
将失败,日期早于 1970 年初的 Unix 纪元.
strtotime()
will fail with dates before the Unix epoch at the start of 1970.
作为替代方案,它适用于 1970 年之前的日期:
As an alternative which will work with dates before 1970:
<?php
// Returns the year as an offset since 1900, negative for years before
$parts = strptime("18951012", "%Y%m%d");
$year = $parts['tm_year'] + 1900; // 1895
$day = $parts['tm_mday']; // 12
$month = $parts['tm_mon']; // 10
?>