在视图中可用的模型状态？

块引用>

当然：

  @if（！ViewData.ModelState.IsValid）
{
    ＆LT; D​​IV＆GT;有一些错误＆LT; / DIV＆GT;
}
 

I have the following in my action method:

       if (!ModelState.IsValid)
        return View(vm);

In the view I want to not present a submit key to allow deletion if the model state is not valid. Is there a way that I can do this? Is model state available in the view?

Update: I have implemented this based on the answers I was given:

            <div class="adm_td0" style=" padding: 0;">  
            @if (ViewData.ModelState.IsValid) {
                <input type='submit' value='Delete' name='SubmitAction' />
            }
                <input type='submit' value='Cancel' name='SubmitAction' />
            </div>

Is model state available in the view?

Of course:

@if (!ViewData.ModelState.IsValid)
{
    <div>There are some errors</div>
}