更新时间:2023-11-30 14:08:10
这是一个非常直接的翻译:
import re
re_domain = re.compile(。* \。(。*))
sites = {}
索引中的索引:
match = re_domain.search(index)
如果匹配:
sites.setdefault(match.group(1),[])。append(index)
site.keys()中的site_key:
devices = sites [site_key]
更多Pythonic的方式就是这样做:
导入集合
导入os.path
sites = collections.defaultdict(list)
用于索引索引:
root,ext = os.path.splitext(索引)
sites [ext] .append( index)
for site_key,sites.iteritems()中的设备:
...
I'm new to python, and can't get my head around dict hashes.
Here's my perl code:
my %sites;
foreach (@indexes) {
push @{$sites{$1}}, $_ if (/.*\.(.*)/);
}
foreach my $sites (keys %sites)
{
@devices = @{$sites{$sites}};
#Do stuff
How do I do the same in Python?
This is a pretty direct translation:
import re
re_domain = re.compile(".*\.(.*)")
sites = {}
for index in indexes:
match = re_domain.search(index)
if match:
sites.setdefault(match.group(1), []).append(index)
for site_key in sites.keys():
devices = sites[site_key]
A more Pythonic way would be to do it like this:
import collections
import os.path
sites = collections.defaultdict(list)
for index in indexes:
root, ext = os.path.splitext(index)
sites[ext].append(index)
for site_key, devices in sites.iteritems():
...