这可以通过利用

This can be done by leveraging the interactive function.

%pylab inline
from ipywidgets import widgets
from IPython.display import display
import numpy as np
import matplotlib

t = np.arange(0.0, 4*pi, 0.01)

def pltsin(f1, f2):
    ax11 = plt.subplot(121)
    ax11.set_title('Plot 1')
    ax11.plot(t, sin(2*pi*t*f1/4/pi), 'k'); ax11.grid(True)
    ax11.plot(t, cos(2*pi*t*f1/4/pi), 'r'); ax11.grid(True)

    ax12 = plt.subplot(122)
    ax12.set_title('Plot 2')
    ax12.plot(t, sin(2*pi*t*f2/4/pi), 'k'); ax12.grid(True)
    ax12.plot(t, cos(2*pi*t*f2/4/pi), 'r'); ax11.grid(True)

    plt.show()

def reset_values(b):
    """Reset the interactive plots to inital values."""
    my_plts.children[0].value = 1
    my_plts.children[1].value = 1

reset_button = widgets.Button(description = "Reset")
reset_button.on_click(reset_values)

my_plts = widgets.interactive(pltsin, f1 = (1, 2, 0.01), f2 = (1, 2, 0.01))
display(my_plts, reset_button)

不能忍受硬编码的变量吗?然后将reset_values函数替换为更具弹性的版本:

Can't stand hard-coded variables? Then replace the reset_values function with this more elastic version:

def reset_values(b):
    """Reset the interactive plots to inital values."""

    my_plts.children[0].value = my_plts.children[0].min
    my_plts.children[1].value = my_plts.children[1].min

希望有帮助.