您可以做更多不仅仅是扩展一个可变参数包作为一个简单的列表：一个表达式。因此，您可以将 m_sequences 作为向量的元组，而不是元素的元组：

You can do more than just expand a variadic parameter pack as a plain list: you can expand an expression too. You can therefore have m_sequences be a tuple of vectors rather than a tuple of the elements:

template <typename... T>
struct sequences
{
   std::tuple<std::vector<T>...> m_sequences;
};

您还可以使用参数包来拾取适当的元素：

You can also do nifty tricks with parameter packs to pick the appropriate element from the vector:

template<size_t ... Indices> struct indices_holder
{};

template<size_t index_to_add,typename Indices=indices_holder<> >
struct make_indices_impl;

template<size_t index_to_add,size_t...existing_indices>
struct make_indices_impl<index_to_add,indices_holder<existing_indices...> >
{
    typedef typename make_indices_impl<
        index_to_add-1,
        indices_holder<index_to_add-1,existing_indices...> >::type type;
};

template<size_t... existing_indices>
struct make_indices_impl<0,indices_holder<existing_indices...> >
{
    typedef indices_holder<existing_indices...>  type;
};

template<size_t max_index>
typename make_indices_impl<max_index>::type make_indices()
{
    return typename make_indices_impl<max_index>::type();
}



template <typename... T>
struct sequences
{
    std::tuple<std::vector<T>...> m_sequences;

    template<size_t... Indices>
    std::tuple<T...> get_impl(size_t pos,indices_holder<Indices...>)
    {
        return std::make_tuple(std::get<Indices>(m_sequences)[pos]...);
    }

    std::tuple<T...> get(size_t pos)
    {
        return get_impl(pos,make_indices<sizeof...(T)>());
    }
};