当然，使用 is_specialization_of （从此处）：

template<typename Type, bool IsTuple = is_specialization_of<Type, std::tuple>::value>
bool f(Type* x);

但问题是，你真的想要那个吗？通常，如果你需要知道一个类型是否是一个元组，你需要对元组进行特殊处理，这通常与模板参数有关。

The question is, however, do you really want that? Normally, if you need to know if a type is a tuple, you need special handling for tuples, and that usually has to do with its template arguments. As such, you might want to stick to your overloaded version.

编辑：由于您提到您只需要一小部分专业版本，因此我建议您重载但仅适用于小的特殊部分：

Since you mentioned you only need a small portion specialized, I recommend overloading but only for the small special part:

template<class T>
bool f(T* x){
  // common parts...
  f_special_part(x);
  // common parts...
}

with

template<class T>
void f_special_part(T* x){ /* general case */ }

template<class... Args>
void f_special_part(std::tuple<Args...>* x){ /* special tuple case */ }