更新时间:2023-12-01 08:25:10
您必须创建一个包含新字段的新 dtype.
You have to create a new dtype that contains the new field.
例如,这里是a
:
In [86]: a
Out[86]:
array([(1, [-112.01268501699997, 40.64249414272372]),
(2, [-111.86145708699996, 40.4945008710162])],
dtype=[('i', '<i8'), ('loc', '<f8', (2,))])
a.dtype.descr
是 [('i', '<i8'), ('loc', '<f8', (2,))]代码>;即字段类型列表.我们将通过将
('USNG', 'S100')
添加到该列表的末尾来创建一个新的数据类型:
a.dtype.descr
is [('i', '<i8'), ('loc', '<f8', (2,))]
; i.e. a list of field types. We'll create a new dtype by adding ('USNG', 'S100')
to the end of that list:
In [87]: new_dt = np.dtype(a.dtype.descr + [('USNG', 'S100')])
现在创建一个新结构化数组,b
.我在这里使用了 zeros
,因此字符串字段将以 ''
值开头.您也可以使用 empty
.字符串随后将包含垃圾,但如果您立即为其赋值,则无关紧要.
Now create a new structured array, b
. I used zeros
here, so the string fields will start out with the value ''
. You could also use empty
. The strings will then contain garbage, but that won't matter if you immediately assign values to them.
In [88]: b = np.zeros(a.shape, dtype=new_dt)
将现有数据从a
复制到b
:
In [89]: b['i'] = a['i']
In [90]: b['loc'] = a['loc']
现在是b
:
In [91]: b
Out[91]:
array([(1, [-112.01268501699997, 40.64249414272372], ''),
(2, [-111.86145708699996, 40.4945008710162], '')],
dtype=[('i', '<i8'), ('loc', '<f8', (2,)), ('USNG', 'S100')])
在新字段中填写一些数据:
Fill in the new field with some data:
In [93]: b['USNG'] = ['FOO', 'BAR']
In [94]: b
Out[94]:
array([(1, [-112.01268501699997, 40.64249414272372], 'FOO'),
(2, [-111.86145708699996, 40.4945008710162], 'BAR')],
dtype=[('i', '<i8'), ('loc', '<f8', (2,)), ('USNG', 'S100')])