这不是 foreach 的工作方式.你应该看看例子.如果要从并行化作业中输出某些内容，则需要使用 .combine.另外，而不是这个:

This is not how foreach works. You should look into examples. You need to use .combine, if you want to output something from your parallelized jobs. Also, instead of this:

sigmaEpsSqV<-as.matrix(sigmaEpsSqV)
SigEpsilonSq[[p]]<-sigmaEpsSqV
SigLSq[[p]]<-sigmaExtSq
RatioMat[[p]]<-ratioMatr 

你必须像这样重写:

list(as.matrix(sigmaEpsSqV),sigmaEpsSqV,sigmaExtSq,ratioMatr)

您还可以使用 rbind、cbind、c、... 将结果聚合为一个最终输出.您甚至可以使用自己的组合功能，例如:

You can also use rbind, cbind, c,... to aggregate the results into one final output. You can even your own combine function, example:

.combine=function(x,y)rbindlist(list(x,y))

下面的解决方案应该有效.输出应该是一个列表列表.然而，检索结果并以正确的格式保存它们可能会很痛苦.如果是这样，您应该设计自己的 .combine 函数.

The solution below should work. The output should be a list of lists. However it might be painful to retreive results and save them in the correct format. If so, you should design your own .combine function.

cl<-makeCluster(core-1)
registerDoParallel(cl,cores=core)
SigEpsilonSq<-list()
SigLSq<-list()
RatioMat<-list()
results = foreach(p=1:100, .combine=list) %dopar%{

  functions defining my variables{...}

  for(i in 1:fMaxInd){
   rhoSqjMatr[,i]<-1/(1+Bb[i])*(CbAdj+AbAdj*XjBarAdj+BbAdj[i]*XjSqBarAdj)/(dataZ*dataZ)
     sigmaEpsSqV[i]<-mean(rhoSqjMatr[,i])
     rhoSqjMatr[,i]<-rhoSqjMatr[,i]/sigmaEpsSqV[i]
     biasCorrV[,i]<-sigmaEpsSqV[i]/L*gammaQl(rhoSqjMatr[,i])
     Qcbar[,i]<-Qflbar-biasCorrV[,i]
     sigmaExtSq[,i]<-sigmaSqExt(sigmaEpsSqV[i], rhoSqjMatr[,i])
     ratioMatr[,i]<-sigmaExtSq[,i]/(sigmaL*sigmaL)#ratio (sigma_l^e)^2/(sigmaL)^2

   }   

   list(as.matrix(sigmaEpsSqV),sigmaEpsSqV,sigmaExtSq,ratioMatr)

} #End of the dopar loop

stopCluster(cl)

#Then you extract and save results