这可能对你有用(GNU sed):

This might work for you (GNU sed):

sed -n ':a;$!{N;s/\n/&/2;Ta};/^PATTERN\'\''/MP;$!D' file

这将打印整个文件中 PATTERN 之前的第 2 行.

This will print the line 2 lines before the PATTERN throughout the file.