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代码在C中打印意外输出

更新时间:2023-12-04 11:43:52

这个数字大于一个整数(有4个字节),它可以容纳2 ^ 31-1和一点符号。



用于电话号码的char数组通常命名为字符串。



谷歌的一些教程。 ; - )

I wrote a very small code in C which basically takes input from user, save in variable and print it out the same input given by user to screen.
But, When I entered "9879041552" it printed out really strange number. Although, some numbers are working fine, the numbers which are limited to 4 digits.
What's causing this unexpected behavior?

#include 
#include 

int main()
{
    int mobileNumber;
    printf("Enter your mobile number: ");
    scanf("%d", &mobileNumber);
    printf("Your mobile number is: %d", mobileNumber);
    
return 0;
}



What I have tried:

I am beginner to programming. I tried searching online but it doesn't give me any reason why this happened.

The number is bigger than an integer (with 4 bytes) which holds up to 2^31-1 and a bit for the sign.

Use for phone numbers a char array often named string.

Google for some tutorials. ;-)