更新时间:2023-12-04 14:19:28
您的data
实例是Vector
.在这行上,
Your data
instance is a Vector
. On this line,
((Vector) data.get(row)).setElementAt(value, col);
您可以使用data.get(row)
从向量中获取单个元素,在您的情况下为String.现在,您正在尝试将String转换为带有(Vector)
的Vector
,这显然是行不通的.
you fetch a single element from the vector with data.get(row)
, which in your case is a String. Now you are trying to convert that String into a Vector
with (Vector)
which obviously doesn't work.
是否要确保向量中的向量安全以生成表格?也许定义通用向量的类型将有助于您发现问题,例如Vector<Vector<String>> data
.
Do you want to safe a vector in a vector to produce a table? Maybe defining the type of the generic vector will help you find your problem, e.g. Vector<Vector<String>> data
.