大概是下面的代码引起了错误；你得到一个错误吗?您还会在捕获任何异常时消耗任何异常，这对诊断问题没有帮助.

Presumably the error is with the code below; do you get an error? You are also consuming any exceptions when caught, which does not help to diagnose the problem.

query="update table1 set name='' "+name_t.getText()+" ''                      where id="+id_t.getText()+")";
                     stat.executeUpdate(query);

您可以使用此代码(针对Google)对SQL注入敞开大门，这有可能损害您的系统.

You are leaving yourself wide open to SQL injection with this code (Google for it), which has the potential to damge your system.