更新时间:2023-12-04 22:07:46
它看起来像错误是在PHP code。
It looks like the error is in the PHP code.
更改以下行: -
发件人:
$query = mysql_query("SELECT * FROM user WHERE username = '$un' AND password = '$pw'");
到
$query = "SELECT * FROM user WHERE username = '$un' AND password = '$pw'";
您也应该考虑改变prevent SQL注入: -
You should also consider making changes to prevent SQL Injection:-
$query = sprintf("SELECT * FROM user WHERE username =
WHERE username='%s' AND password='%s'",
mysql_real_escape_string($un),
mysql_real_escape_string($pw));