没有循环和复杂性在各种需要awk的匹配（和打印）：

No looping or complexity needed for awk to match (and print) in a range:

awk 'NR>start && NR<end && /pattern/'

一个有点棘手文件B的内容转换成正确的 AWK 的条件，但这是：

A bit trickier to convert file B content to the right awk condition, but this does it:

echo "($(awk 'NR==1{r1=$1;next}
              NR>2{printf"||"}
              {printf"(NR>%d&&NR<%d)",r1,$1;r1=$1}
              END{if(NR<2)printf"0"}' B))&&/yourpattern/"|
  awk -f- A

也许稍微简单的将是pre-过滤器使用SED的范围，然后用grep的格局：

Perhaps slightly simpler would be to pre-filter the ranges using sed, and then grep for the pattern:

awk 'NR==1{r1=$1;next}
     $1>r1+1{printf"%d,%dp\n",r1+1,$1-1;r1=$1}' B|
  sed -nf- A|
  grep 'yourpattern'