如果所有列表都存储在列表 a 中，

If you have all of your lists stored in a list a,

# a = [[.45], [.87], ...]
import itertools
output = list(itertools.chain(*a))

此答案之所以比其他答案更好，是因为它整齐地将任意数量的列表连接在一起，而不需要 for 循环之类的东西.

What makes this answer better than the others is that it neatly joins an arbitrary number of lists together in one line, without a need for a for loop or anything like that.