过滤器(或列表理解)是解决之道.如果您想就地执行此操作，则可以执行以下操作:

Filter (or list comprehension) IS the way to go. If you want to do it inplace, something like this would work:

purge = []
for i,object in enumerate(self.list):
    if object.mycond()
        purge.append(i)
for i in reversed(purge):
    del self.list[i]

或者，可以通过理解来创建清除列表，快捷方式如下:

Or alternatively, the purge list can be made with a comprehension, a shortcut version looks like:

for i in reversed([ i for (i,o) in enumerate(self.list) if o.mycond() ]):
    del self.list[i]