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在Google脚本中使用appendParagraph时,图像会自我复制

更新时间:2023-12-05 21:28:22

关于原因,我什至没有丝毫线索,但是我找到了一种使这项工作成功的方法.

切换代码的​​顺序似乎可以解决问题.我只是简单地将图像插入代码移到了 end (即之后 appendParagraph 代码),就可以正常工作了.没有重复的图片!

  function myFunction(e){var doc = DocumentApp.create('fileTest');var body = doc.getBody();body.appendParagraph('测试文本的测试行');var matchedFiles = DriveApp.getFilesByName('logo.png');如果(matchedFiles.hasNext()){var image = matchedFiles.next().getBlob();varlocatedImage = body.getParagraphs()[0] .addPositionedImage(image);}doc.saveAndClose();} 

I wrote a script to add an image from my Google Drive and some custom text to a Google Doc. (I got the image insertion code from here). The resulting document is created ok, but my image is added twice for some reason...

function myFunction(e) {

  var doc = DocumentApp.create('fileTest');
  var body = doc.getBody();

   var matchedFiles = DriveApp.getFilesByName('logo.png');
   if (matchedFiles.hasNext()) {
    var image = matchedFiles.next().getBlob(); 
     var positionedImage = body.getParagraphs()[0].addPositionedImage(image);
   }

  body.appendParagraph('Test line of text for testing');

  doc.saveAndClose();

}

However, if I get rid of my appendParagraph code (body.appendParagraph(t1);) I only get one image (but obviously without the paragraph of text I want)

What's going on here? And how do I add both one picture and my paragraph of text?

I have not even the slightest clue as to why, but I found a way to make this work.

Switching the order of my code seemed to do the trick. I simply moved the image-insertion code to the end (i.e., after the appendParagraph code), and it worked fine. No duplicate image!

function myFunction(e) {

  var doc = DocumentApp.create('fileTest');
  var body = doc.getBody();

  body.appendParagraph('Test line of text for testing');

   var matchedFiles = DriveApp.getFilesByName('logo.png');
   if (matchedFiles.hasNext()) {
    var image = matchedFiles.next().getBlob(); 
     var positionedImage = body.getParagraphs()[0].addPositionedImage(image);
   }

  doc.saveAndClose();

}