请参阅： Directory.GetFiles [ ^ ]

它给出的示例的修改版本：

See here: Directory.GetFiles[^]
A modified version of the example it gives:

array<String^>^dirs = Directory::GetFiles( "D:\\Temp\\", "myfile.*" );
Console::WriteLine( "Found: {0}", dirs->Length );

数组将包含每个文件的完整路径，包括扩展名。

The array will contain the full path to each file, including the extension.