更新时间:2022-04-04 23:57:57
std::set
的第二个模板参数必须是 type,而不是 价值.
The second template argument to std::set
has to be a type, not value .
如果你想使用函数(它是值,而不是类型),那么你必须将它作为参数传递给构造函数,这意味着你可以这样做这个:
If you want to use function (which is value, not type), then you've to pass it as argument to the constructor, which means you can do this:
class Renderer
{
typedef bool (*ComparerType)(Mesh const&,Mesh const&);
std::set<Mesh, ComparerType> m_Meshes;
public:
Renderer() : m_Meshes(MeshCompare)
{ //^^^^^^^^^^^^^^^^^^^^^^^ note this
}
};
或者,定义一个函子类,并将其作为第二个 type 参数传递给 std::set
.
struct MeshComparer
{
bool operator()(const Mesh& a, const Mesh& b) const
{
return ( (a.pTech < b.pTech) ||
( (b.pTech == a.pTech) && (a.pMaterial < b.pMaterial) ) ||
( (b.pTech == a.pTech) && (a.pMaterial == b.pMaterial) && (a.topology < b.topology) ) );
}
};
然后使用它:
std::set<Mesh, MeshComparer> m_Meshes;