更新时间:2022-06-09 01:06:25
折叠表达式 17:
template <typename T, typename... U>
typename std::enable_if<(std::is_same<U, float>::value && ...), void>::
type testFunction(T a, U... bs) {
std::cout << "bs are floats\n";
}
在C ++ 11中,您可以重新实现 std :: conjunction
:
In C++11, you can reimplement std::conjunction
:
template<class...> struct conjunction : std::true_type { };
template<class B1> struct conjunction<B1> : B1 { };
template<class B1, class... Bn>
struct conjunction<B1, Bn...>
: std::conditional_t<bool(B1::value), conjunction<Bn...>, B1> {};
template <typename T, typename... U>
typename std::enable_if<
std::conjunction_v<std::is_same<U, float>...>,
void
>::type testFunction(T a, U... bs) {
std::cout << "bs are floats\n";
}