这是我能想到的最简单的例子，没有经过测试.请注意，这使用了一些不好的做法，并且与您通常使用 C++ 的方式不同(初始化列表、声明和定义的分离等).但这些是我无法在此涵盖的主题.

This is the most simple example I can think of in this case and is not tested. Please consider that this uses some bad practices and does not go the way you normally would go with C++ (initialize lists, separation of declaration and definition, and so on). But that are topics I can't cover here.

#include <iostream>
using namespace std;

class LinkedList{
    // Struct inside the class LinkedList
    // This is one node which is not needed by the caller. It is just
    // for internal work.
    struct Node {
        int x;
        Node *next;
    };

// public member
public:
    // constructor
    LinkedList(){
        head = NULL; // set head to NULL
    }

    // destructor
    ~LinkedList(){
        Node *next = head;
        
        while(next) {              // iterate over all elements
            Node *deleteMe = next;
            next = next->next;     // save pointer to the next element
            delete deleteMe;       // delete the current entry
        }
    }
    
    // This prepends a new value at the beginning of the list
    void addValue(int val){
        Node *n = new Node();   // create new Node
        n->x = val;             // set value
        n->next = head;         // make the node point to the next node.
                                //  If the list is empty, this is NULL, so the end of the list --> OK
        head = n;               // last but not least, make the head point at the new node.
    }

    // returns the first element in the list and deletes the Node.
    // caution, no error-checking here!
    int popValue(){
        Node *n = head;
        int ret = n->x;

        head = head->next;
        delete n;
        return ret;
    }

// private member
private:
    Node *head; // this is the private member variable. It is just a pointer to the first Node
};

int main() {
    LinkedList list;

    list.addValue(5);
    list.addValue(10);
    list.addValue(20);

    cout << list.popValue() << endl;
    cout << list.popValue() << endl;
    cout << list.popValue() << endl;
    // because there is no error checking in popValue(), the following
    // is undefined behavior. Probably the program will crash, because
    // there are no more values in the list.
    // cout << list.popValue() << endl;
    return 0;
}

我强烈建议您阅读一些有关 C++ 和面向对象编程的内容.一个好的起点可能是这样的:http://www.galileocomputing.de/1278?GPP=opoo

I would strongly suggest you to read a little bit about C++ and Object oriented programming. A good starting point could be this: http://www.galileocomputing.de/1278?GPP=opoo

添加了弹出功能和一些输出.如您所见，程序推送了 3 个值 5、10、20，然后将它们弹出.之后顺序颠倒了，因为这个列表在堆栈模式下工作(LIFO，后进先出)

added a pop function and some output. As you can see the program pushes 3 values 5, 10, 20 and afterwards pops them. The order is reversed afterwards because this list works in stack mode (LIFO, Last in First out)