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Winforms DataGridView将数据绑定到复杂类型/嵌套属性

更新时间:2022-06-02 17:49:17

德米特法律

在MyClass上创建一个暴露SubClass.Property的属性。像这样:

Create a property on MyClass that exposes the SubClass.Property. Like so:

public class MyClass
{
   private SubClass _mySubClass;

   public MyClass(SubClass subClass)
   {
      _mySubClass = subClass;
   }

   public PropertyType Property
   {
      get { return _subClass.Property;}
   }   
}