更新时间:2022-06-16 09:21:49
Boost有 apply_visitor
函数,它接受一个通用函数对象和将变体的类型传递给它。因此,实现运算符<<
非常简单:
Boost has an apply_visitor
function, that takes a generic function object and passes the type of the variant into it. So implementing operator<<
is as straightforward as:
template <class... Ts>
std::ostream& operator<<(std::ostream& os, boost::variant<Ts...> const& var) {
return boost::apply_visitor(ostream_visitor{os}, var);
}
与:
struct ostream_visitor : boost::static_visitor<std::ostream&>
{
std::ostream& os;
template <class T>
std::ostream& operator()(T const& val) {
return os << val;
}
};
或者:
template <class... Ts>
std::ostream& operator<<(std::ostream& os, boost::variant<Ts...> const& var) {
return boost::apply_visitor([&os](const auto& val) -> std::ostream& {
return os << val;
}, var);
}
您可以在教程。