我建议使用2种方法:

In [212]:

df = pd.DataFrame({'entrytype':[0,1,np.NaN, 'asdas',2]})
df
Out[212]:
  entrytype
0         0
1         1
2       NaN
3     asdas
4         2

如果值的范围受到您的限制，则使用isin将是最快的方法:

If the range of values is as restricted as you say then using isin will be the fastest method:

In [216]:

df[df['entrytype'].isin([0,1,2])]
Out[216]:
  entrytype
0         0
1         1
4         2

否则我们可以强制转换为str，然后调用.isdigit()

Otherwise we could cast to a str and then call .isdigit()

In [215]:

df[df['entrytype'].apply(lambda x: str(x).isdigit())]
Out[215]:
  entrytype
0         0
1         1
4         2