这就是您需要的

方法1:将名称添加到数组

数据

{"data":[{"identifier" : "id#1","dataA" : "dataA#1"},{"identifier" : "id#2","dataA" : "dataA#2"}]}

SQL

SET hive.support.sql11.reserved.keywords=false;

CREATE EXTERNAL TABLE IF NOT EXISTS ramesh_test (
  data array<
    struct<
      identifier:STRING, 
      dataA:STRING
    >
  >
)
ROW FORMAT SERDE 'org.openx.data.jsonserde.JsonSerDe'
LOCATION 'my_location';

SELECT rows.identifier,
       rows.dataA
  FROM ramesh_test d
LATERAL VIEW EXPLODE(d.data) d1 AS rows  ;

输出

方法2-数据无变化

数据

[{"identifier":"id#1","dataA":"dataA#1"},{"identifier":"id#2","dataA":"dataA#2"}]

SQL

CREATE EXTERNAL TABLE IF NOT EXISTS ramesh_raw_json (
  json STRING
)
LOCATION 'my_location';

SELECT get_json_object (exp.json_object, '$.identifier') AS Identifier,
       get_json_object (exp.json_object, '$.dataA') AS Identifier
  FROM ( SELECT json_object
           FROM ramesh_raw_json a
           LATERAL VIEW EXPLODE (split(regexp_replace(regexp_replace(a.json,'\\}\\,\\{','\\}\\;\\{'),'\\[|\\]',''), '\\;')) json_exploded AS json_object ) exp;

输出