您已经接受了答案。为了显示匹配和控制匹配的更多扩展，这可能在将来帮助您：

As you already accepted an answer. To show some more extend of matching and controlling the matches, this might help you in the future:

var url = 'http://link.com//whatever///';
var set = url.match(/([^:]\/{2,3})/g); // Match (NOT ":") followed by (2 OR 3 "/")

for (var str in set) {
    // Modify the data you have
    var replace_with = set[str].substr(0, 1) + '/';

    // Replace the match
    url = url.replace(set[str], replace_with);
}

console.log(url);

将输出：

http://link.com/whatever/

Doublets无关紧要在你的情况下。如果你有这个字符串：

Doublets won't matter in your situation. If you have this string:

var url = 'http://link.com//om/om/om/om/om///';

您的 set 数组将包含多个米// 。有点多余，因为循环会看到该变量几次。好处是 String.replace（）如果什么都没找到则不替换任何内容，所以不会造成任何伤害。

Your set array will contain multiple m//. A bit redundant, as the loop will see that variable a few times. The nice thing is that String.replace() replaces nothing if it finds nothing, so no harm done.

您可以做的是首先从 set 中删除​​重复项，但这几乎需要相同数量的资源，只需让for循环遍历它们。

What you could do is strip out the duplicates from set first, but that would almost require the same amount of resources as just letting the for-loop go over them.

祝你好运！