这可能可以清除，但它可以工作并处理嵌套的StructType:

This can probably be cleaned up, but it works and handles nested StructType:

def isEqual(struct1: StructType, struct2: StructType): Boolean = {
  struct1.headOption match {
    case Some(field) => {
      if(field.dataType.typeName != "struct") {
        struct2.find(_ == field) match {
         case Some(matchedField) => isEqual(StructType(struct1.filterNot(_ == field)), StructType(struct2.filterNot(_ == field)))
         case None => false
        }
      } else {
        val isEqualContents = struct2.find(x => x.name == field.name && x.nullable == field.nullable && x.dataType.typeName == "struct") match {
          case Some(matchedField) => isEqual(field.dataType.asInstanceOf[StructType], matchedField.dataType.asInstanceOf[StructType])
          case None => false
        }
        if(isEqualContents) isEqual(StructType(struct1.filterNot(_ == field)), StructType(struct2.filterNot(_ == field))) else false
      }
    }
    case None => struct2.size == 0
  }
}

val st1 = StructType(
StructField("ii",StringType,true) :: 
StructField("i",StringType,true) :: 
StructField("iii", StructType(StructField("iv", StringType, true) :: Nil), true) :: Nil)

val st2 = StructType(
StructField("i",StringType,true) :: 
StructField("ii",StringType,true) :: 
StructField("iii", StructType(StructField("v", StringType, true) :: Nil), true) :: Nil)

isEqual(st1, st2)

它也可以使用更多的爱来成为尾递归.

It could also use a little more love to become tail recursive, too.