Shelly写道：

Shelly wrote:

我有两个表格一页。在表格A中，我有下拉列表（单个

选择）。当我单击表单B中的提交按钮时，我想获取表单A下拉列表中显示的值

。可以这样做吗？


将两个表单分开的原因是表单A打开一个新的浏览器

窗口，并选择该表单，而表单B将它保存在同一个

浏览器中它的选择窗口。但是，下拉列表值是两个中使用的
，我不想在表单B中重复该列表。


Shelly

I have two forms on one page. In Form A I have drop-down list (single
selection). When I click a submit button in form B, I would like to pick up
the value showing in the drop down list of Form A. Can this be done?

The reason for separating the two forms is that Form A opens a new browser
window with selection in that form, whereas Form B keeps it in the same
browser window for its selections. The drop-down list value, however, is
used in both and I would not want to repeat that list in Form B.

Shelly

你可以通过JavaScript或AJAX来实现，你能为我们提供

代码，所以我可以向你解释一下吗？

-------------------------------------------- ------------------------------------------


有关php / ajax / javascript教程和提示，请访问我的博客
http://www.nurazije.co.nr

You can do it by JavaScript or by AJAX, can you provide us with the
code, so I can explain to you eaisier ??
--------------------------------------------------------------------------------------

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>

Shelly写道：

>
Shelly wrote:

>我在一个页面上有两个表单。在表格A中，我有下拉列表（单个选项）。当我单击表单B中的提交按钮时，我想选择
显示表单A下拉列表中显示的值。可以这样做吗？

分离这两个表单的原因是表单A打开一个新的
浏览器窗口，其中包含该表单中的选择，而表单B将其保存在相同的浏览器窗口中以供选择。但是，下拉列表值在两者中都使用了，我不想在表单B中重复该列表。

Shelly

>I have two forms on one page. In Form A I have drop-down list (single
selection). When I click a submit button in form B, I would like to pick
up
the value showing in the drop down list of Form A. Can this be done?

The reason for separating the two forms is that Form A opens a new
browser
window with selection in that form, whereas Form B keeps it in the same
browser window for its selections. The drop-down list value, however, is
used in both and I would not want to repeat that list in Form B.

Shelly

你可以通过JavaScript或AJAX来实现，你能为我们提供

代码，所以我可以向你解释一下吗？

You can do it by JavaScript or by AJAX, can you provide us with the
code, so I can explain to you eaisier ??

我不知道AJAX。


[php code]

< ？php

if（isset（

I don''t know AJAX.

[ php code]
<?php
if (isset(

_POST [''A'']））{

_POST[''A''])) {