显然，这不是错误，它是预期的 ，但没有记录的行为'^{查看对错误报告的评论} 。所有单个字母（ j除外）都代表军事时区，请参阅一些代码来演示这一点。

Apparently, this is not a bug, it is 'expected, but undocumented behaviour'^{See the comments to the bug report}. All single letters (except for 'j') represent military timezones, see some code to demonstrate this.

有更多信息此处。

来自 RFC822

军事标准在每个区域使用一个字符。 Z是世界标准时间。 A表示提前一小时， M表示提前十二小时； N是一小时后， Y是十二小时后。

The military standard uses a single character for each zone. "Z" is Universal Time. "A" indicates one hour earlier, and "M" indicates 12 hours earlier; "N" is one hour later, and "Y" is 12 hours later. The letter "J" is not used.

所以回答您的问题

我不明白这一点，它是如何工作的？

I am not getting the point, how it's working?

当DateTime :: __ construct（）时传递了一个不是有效时间字符串的单一值，它假定第一个参数已被省略，并尝试将字符串解析为时区。正如RFC解释的那样， x是有效的时区，因此您将获得位于时区 X中的DateTime实例。

When DateTime::__construct() is passed a single value that is not a valid time string it assumes that the first parameter has been omitted and tries to parse the string as a time zone. As the RFC explains, 'x' is a valid timezone, so you will get a DateTime instance that is in timezone 'X'.

我应该提到，尽管构造函数的\DateTime识别这些单个字母区域，\DateTimeZone的构造函数不会！

I should mention that although the constructor of \DateTime recognises these single letter zones, the constructor of \DateTimeZone does not!

我希望能帮上忙。