更新时间:2021-08-25 23:04:46
您可以在 onResponse
方法中进行操作,请记住 400 是响应状态,不是错误:
You can do it in your onResponse
method, remember 400 is a response status not an error:
if (response.code() == 400) {
Log.v("Error code 400",response.errorBody().string());
}
您可以使用 Gson
来处理除200-300 之外的任何响应代码,如下所示:
And you can handle any response code except 200-300 with Gson
like that:
if (response.code() == 400) {
Gson gson = new GsonBuilder().create();
ErrorPojoClass mError=new ErrorPojoClass();
try {
mError= gson.fromJson(response.errorBody().string(),ErrorPojoClass.class);
Toast.makeText(context, mError.getDescription(), Toast.LENGTH_LONG).show();
} catch (IOException e) {
// handle failure to read error
}
}
将此添加到您的 build.gradle
中:编译'com.google.code.gson:gson:2.7'
如果要创建 Pojo
类,请转到 Json Schema 2 Pojo 并粘贴您的示例 Json
响应.选择源类型 Json 和注释 Gson .
If you want create Pojo
class go to Json Schema 2 Pojo and paste your example Json
response. Select source type Json and annotation Gson .