更新时间:2022-05-09 22:22:34
请根据您的要求试用此代码:
Plese try this code according to your requirement:
来源页面:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
Name:
<input type="text" id="txtName" name="Name" value="Mudassar Khan" /><br />
<br />
Technology:
<select id="ddlTechnolgy" name="Technology">
<option value="ASP.Net">ASP.Net</option>
<option value="PHP">PHP</option>
<option value="JSP">JSP</option>
</select>
<input type="button" id="btnQueryString" value="Send" />
<script type="text/javascript">
$(function () {
$("#btnQueryString").bind("click", function () {
var url = "Page2.htm?name=" + encodeURIComponent($("#txtName").val()) + "&technology=" + encodeURIComponent($("#ddlTechnolgy").val());
window.location.href = url;
});
});
</script>
目标网页
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<span id = "lblData"></span>
<script type="text/javascript">
var queryString = new Array();
$(function () {
if (queryString.length == 0) {
if (window.location.search.split('?').length > 1) {
var params = window.location.search.split('?')[1].split('&');
for (var i = 0; i < params.length; i++) {
var key = params[i].split('=')[0];
var value = decodeURIComponent(params[i].split('=')[1]);
queryString[key] = value;
}
}
}
if (queryString["name"] != null && queryString["technology"] != null) {
var data = "<u>Values from QueryString</u><br /><br />";
data += "<b>Name:</b> " + queryString["name"] + " <b>Technology:</b> " + queryString["technology"];
$("#lblData").html(data);
}
});
</script>