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且构网 - 分享程序员编程开发的那些事

如何使用html将值传递到另一个页面

更新时间:2022-05-09 22:22:34

请根据您的要求试用此代码:

Plese try this code according to your requirement:

来源页面:

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
Name:
<input type="text" id="txtName" name="Name" value="Mudassar Khan" /><br />
<br />
Technology:
<select id="ddlTechnolgy" name="Technology">
    <option value="ASP.Net">ASP.Net</option>
    <option value="PHP">PHP</option>
    <option value="JSP">JSP</option>
</select>

<input type="button" id="btnQueryString" value="Send" />
<script type="text/javascript">
    $(function () {
        $("#btnQueryString").bind("click", function () {
            var url = "Page2.htm?name=" + encodeURIComponent($("#txtName").val()) + "&technology=" + encodeURIComponent($("#ddlTechnolgy").val());
            window.location.href = url;
        });
    });
</script>

目标网页

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<span id = "lblData"></span>

<script type="text/javascript">
    var queryString = new Array();
    $(function () {
        if (queryString.length == 0) {
            if (window.location.search.split('?').length > 1) {
                var params = window.location.search.split('?')[1].split('&');
                for (var i = 0; i < params.length; i++) {
                    var key = params[i].split('=')[0];
                    var value = decodeURIComponent(params[i].split('=')[1]);
                    queryString[key] = value;
                }
            }
        }
        if (queryString["name"] != null && queryString["technology"] != null) {
            var data = "<u>Values from QueryString</u><br /><br />";
            data += "<b>Name:</b> " + queryString["name"] + " <b>Technology:</b> " + queryString["technology"];
            $("#lblData").html(data);
        }
    });
</script>