更新时间:2021-10-14 23:16:10
在数据库字段中使用逗号分隔列表是一种反模式,应不惜一切代价避免.
因为在 SQL 中再次提取这些逗号分隔的值是一个 PITA.
Using comma separated lists in a database field is an anti-pattern and should be avoided at all costs.
Because it is a PITA to extract those comma separated values out agian in SQL.
相反,您应该添加一个单独的链接表来表示类别和电影之间的关系,如下所示:
Instead you should add a separate link table to represent the relationship between categories and movies, like so:
Table categories
id integer auto_increment primary key
name varchar(255)
Table movies
id integer auto_increment primary key
name varchar(255)
Table movie_cat
movie_id integer foreign key references movies.id
cat_id integer foreign key references categories.id
primary key (movie_id, cat_id)
现在可以了
SELECT m.name as movie_title, GROUP_CONCAT(c.name) AS categories FROM movies m
INNER JOIN movie_cat mc ON (mc.movie_id = m.id)
INNER JOIN categories c ON (c.id = mc.cat_id)
GROUP BY m.id
回到你的问题
或者,您可以使用您的数据
Back to your question
Alternativly using your data you can do
SELECT m.name as movie_title
, CONCAT(c1.name, if(c2.name IS NULL,'',', '), ifnull(c2.name,'')) as categories
FROM movies m
LEFT JOIN categories c2 ON
(replace(substring(substring_index(m.categories, ',', 2),
length(substring_index(m.categories, ',', 2 - 1)) + 1), ',', '') = c2.id)
INNER JOIN categories c1 ON
(replace(substring(substring_index(m.categories, ',', 1),
length(substring_index(m.categories, ',', 1 - 1)) + 1), ',', '') = c1.id)
请注意,最后一个查询仅适用于每部电影有 2 个或更少类别的情况.
Note that the last query only works if there are 2 or fewer categories per movie.