If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

sum = 0;
for number in range(1,1000):
    if (number % 3 == 0) or (number % 5 == 0):
        sum += number
        print 'The sum is:', sum, 'The current number is', number