对PostgreSQL Merge Join 的理解

更新时间：2022-09-13 19:01:47

开始

伪代码:

http://momjian.us/main/writings/pgsql/optimizer.pdf

sort(outer);            
sort(inner);            
i = 0;            
j = 0;            
save_j = 0;            
while (i < length(outer))            
{            
    if (outer[i] == inner[j])        
        output(outer[i], inner[j]);    
            
            
    if (outer[i] <= inner[j] && j < length(inner))        
    {        
        j++;    
        if (outer[i] < inner[j])    
            save_j = j;
    }        
    else        
    {        
        i++;    
        j = save_j;    
    }        
}

上述描述中，可以把两列排序好的数组看成由大到小排列。

Merge Join 先要对各表各自排序，然后从各自的排序表中抽取数据，到另一个排序表中做匹配。
通常来讲，能够使用merge join的地方，hash join 更快。

验证：

postgres=# EXPLAIN SELECT relname,nspname FROM pg_class join
        pg_namespace ON (pg_class.relnamespace = pg_namespace.oid);
                               QUERY PLAN                                
-------------------------------------------------------------------------
 Hash Join  (cost=1.14..16.02 rows=290 width=128)
   Hash Cond: (pg_class.relnamespace = pg_namespace.oid)
   ->  Seq Scan on pg_class  (cost=0.00..10.90 rows=290 width=68)
   ->  Hash  (cost=1.06..1.06 rows=6 width=68)
         ->  Seq Scan on pg_namespace  (cost=0.00..1.06 rows=6 width=68)
(5 rows)

postgres=# 



postgres=# set session enable_hashjoin=false;
SET
postgres=# EXPLAIN SELECT relname,nspname FROM pg_class join
        pg_namespace ON (pg_class.relnamespace = pg_namespace.oid);
                               QUERY PLAN                                
-------------------------------------------------------------------------
 Merge Join  (cost=23.90..28.28 rows=290 width=128)
   Merge Cond: (pg_namespace.oid = pg_class.relnamespace)
   ->  Sort  (cost=1.14..1.15 rows=6 width=68)
         Sort Key: pg_namespace.oid
         ->  Seq Scan on pg_namespace  (cost=0.00..1.06 rows=6 width=68)
   ->  Sort  (cost=22.76..23.49 rows=290 width=68)
         Sort Key: pg_class.relnamespace
         ->  Seq Scan on pg_class  (cost=0.00..10.90 rows=290 width=68)
(8 rows)

postgres=#

[作者：技术者高健@博客园 mail: luckyjackgao@gmail.com ]

改了 join 的顺序对结果也没有影响。

postgres=# EXPLAIN SELECT relname,nspname FROM pg_namespace join
        pg_class ON (pg_class.relnamespace = pg_namespace.oid);
                               QUERY PLAN                                
-------------------------------------------------------------------------
 Merge Join  (cost=23.90..28.28 rows=290 width=128)
   Merge Cond: (pg_namespace.oid = pg_class.relnamespace)
   ->  Sort  (cost=1.14..1.15 rows=6 width=68)
         Sort Key: pg_namespace.oid
         ->  Seq Scan on pg_namespace  (cost=0.00..1.06 rows=6 width=68)
   ->  Sort  (cost=22.76..23.49 rows=290 width=68)
         Sort Key: pg_class.relnamespace
         ->  Seq Scan on pg_class  (cost=0.00..10.90 rows=290 width=68)
(8 rows)

postgres=#

postgres=# EXPLAIN SELECT relname,nspname FROM pg_namespace,
        pg_class where (pg_class.relnamespace = pg_namespace.oid);
                               QUERY PLAN                                
-------------------------------------------------------------------------
 Merge Join  (cost=23.90..28.28 rows=290 width=128)
   Merge Cond: (pg_namespace.oid = pg_class.relnamespace)
   ->  Sort  (cost=1.14..1.15 rows=6 width=68)
         Sort Key: pg_namespace.oid
         ->  Seq Scan on pg_namespace  (cost=0.00..1.06 rows=6 width=68)
   ->  Sort  (cost=22.76..23.49 rows=290 width=68)
         Sort Key: pg_class.relnamespace
         ->  Seq Scan on pg_class  (cost=0.00..10.90 rows=290 width=68)
(8 rows)

postgres=#

结束

本文转自健哥的数据花园博客园博客，原文链接：http://www.cnblogs.com/gaojian/archive/2012/11/08/2760677.html，如需转载请自行联系原作者

上一篇 : ：oracle exp出现"ORA-00302:必须说明SET_NO_OUTLINES 组件" 解决方法下一篇 : 使用Oracle SQLDeveloper连接数据库并创建用户

对PostgreSQL Merge Join 的理解

相关阅读

推荐文章