您不需要任何条件结构来跳过引号内的内容.有两种方式.

You do not need any conditional constructs to skip what is inside quotes. There are two ways.

使用与带引号的子字符串匹配的替代分支并使用 (*SKIP)(*FAIL) 动词:

Use an alternative branch matching a quoted substring and use (*SKIP)(*FAIL) verbs:

 preg_replace('/"[^"]*"(*SKIP)(*F)|creat(?:e|ing)/i', 'make', $input)

模式详情:

• "[^"]*" - 匹配 "，然后是除 " 之外的 0+ 个字符，然后是 "
• (*SKIP)(*F) - 使正则表达式引擎丢弃当前匹配的文本并从当前索引开始
• | - 或...
• creat(?:e|ing) - 匹配 create 或 creating.

• "[^"]*" - matches ", then 0+ characters other than " and then a "
• (*SKIP)(*F) - make the regex engine discard the currently matched text and proceed from the current index
• | - or...
• creat(?:e|ing) - match create or creating.

参见演示

另一种方法是仅使用捕获和使用 preg_replace_callback，您可以在其中检查组是否匹配(并适当地建立替换逻辑):

Another way is mere using capturing and using preg_replace_callback where you can check if a group was matched (and base the replacement logic appropriately):

 preg_replace_callback('/("[^"]*")|creat(?:e|ing)/i', function($m) {
     return !empty($m[1]) ? $m[1] : 'make';
 }, $input)

查看 IDEONE 演示

模式详情:

• ("[^"]*") - 第 1 组(稍后可以使用替换模式中的 $1 引用) - 双引号字符串
• | - 或
• creat(?:e|ing) - 匹配 create 或 creating.

• ("[^"]*") - Group 1 (can be later referenced with $1 from the replacement pattern) - a double quoted string
• | - or
• creat(?:e|ing) - match create or creating.

注意"[^"]*"是一个示例正则表达式，如果你需要匹配带有转义序列的C字符串，你至少应该使用"[^"\\\\]*(?:\\\\.[^"\\\\]*)*"(在代码中).

Note that "[^"]*" is a sample regex, if you need to match C strings with escaped sequences, you should use at least "[^"\\\\]*(?:\\\\.[^"\\\\]*)*" (in the code).