且构网

分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

GNU make manual 翻译( 一百七十九)

更新时间:2022-09-26 08:03:11

继续翻译

GNU make manual 翻译( 一百七十九)
   As this example illustrates, conditionals work at the textual level:
the lines of the conditional are treated as part of the makefile, or
ignored, according to the condition.  This is why the larger syntactic
units of the makefile, such as rules, may cross the beginning or the
end of the conditional.

   When the variable `CC' has the value `gcc', the above example has
this effect:

     foo: $(objects)
             $(CC) -o foo $(objects) $(libs_for_gcc)

When the variable `CC' has any other value, the effect is this:

     foo: $(objects)
             $(CC) -o foo $(objects) $(normal_libs)

   Equivalent results can be obtained in another way by
conditionalizing a variable assignment and then using the variable
unconditionally:

     libs_for_gcc = -lgnu
     normal_libs =

     ifeq ($(CC),gcc)
       libs=$(libs_for_gcc)
     else
       libs=$(normal_libs)
     endif

     foo: $(objects)
             $(CC) -o foo $(objects) $(libs) 
GNU make manual 翻译( 一百七十九)

正如这个例子所揭示的那样,条件式在文本层面上工作:条件式的行被当作makefile的一部分,或者被忽略,这取决于条件本身。这就是为什么makefile中的大一些的语法单位,例如规则,可以跨越条件式的开始或终了之处。

当变量CC拥有值gcc, 上述的例子有如下的效果:

foo: $(objects)
$(CC) -o foo $(objects) $(libs_for_gcc)

如果变量 CC 有其他的值,则效果如下:

foo: $(objects)
$(CC) -o foo $(objects) $(normal_libs)

用另外的方法可以得到同样的结果--把一个对变量的赋值进行条件化,然后使用此变量。

libs_for_gcc = -lgnu
normal_libs =

ifeq ($(CC),gcc)
libs=$(libs_for_gcc)
else
libs=$(normal_libs)
endif

foo: $(objects)
$(CC) -o foo $(objects) $(libs)

后文待续








本文转自健哥的数据花园博客园博客,原文链接:http://www.cnblogs.com/gaojian/archive/2012/10/08/2712244.html,如需转载请自行联系原作者