来自@AChampion的建议。

From @AChampion's suggestion.

>>> import re
>>> import ast
>>> x = ast.literal_eval(re.search('({.+})', data).group(0))
>>> x
{'Bar': 'value', 'Foo': '1002803'}

因此您要寻找的模式是 re.search（'（{。+}）'，data）

so the pattern you're looking for is re.search('({.+})', data)

您应该使用字符串提取花括号，因此 ast.literal_eval 可以将字符串转换为python字典。您也不需要 r 前缀作为 {或} 在捕获组中，（）会按字面值进行匹配。

You were supposed to extract the curly braces with the string, so ast.literal_eval can convert the string to a python dictionary . you also don't need the r prefix as { or } in a capturing group, () would be matched literally.